a)
∫x3dx=(x44)24=444−244=64−4=60\int{x^3}dx=(\frac{x^4}{4})_2^4=\frac{4^4}{4}-\frac{2^4}{4}=64-4=60∫x3dx=(4x4)24=444−424=64−4=60
b)
∫(10+x2)dx=(10x+x33)24=\int({10+x^2})dx=(10x+\frac{x^3}{3})_2^4=∫(10+x2)dx=(10x+3x3)24=
=10⋅4+433−10⋅2−233=38.67=10\cdot 4+\frac{4^3}{3}-10\cdot 2-\frac{2^3}{3}=38.67=10⋅4+343−10⋅2−323=38.67
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