A ball P of mass 2 kg undergoes an elastic collision with another ball Q at rest.After collision, ball P continues to move in its original direction with a speed one fourth of its original speed.What is the mass of the ball Q?
"mv=mv\/4+Mu\\to2v=v\/2+Mu\\to Mu=1.5v"
"mv^2\/2=m(v\/4)^2\/2+Mu^2\\to mv^2=mv^2\/16+M^2u^2\/M"
"2v^2=v^2\/8+(1.5v)^2\/M\\to 2=1\/8+2.25\/M\\to M=1.2kg" Answer.
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