A ball P of mass 2 kg undergoes an elastic collision with another ball Q at rest.After collision, ball P continues to move in its original direction with a speed one fourth of its original speed.What is the mass of the ball Q?
mv=mv/4+Mu→2v=v/2+Mu→Mu=1.5vmv=mv/4+Mu\to2v=v/2+Mu\to Mu=1.5vmv=mv/4+Mu→2v=v/2+Mu→Mu=1.5v
mv2/2=m(v/4)2/2+Mu2→mv2=mv2/16+M2u2/Mmv^2/2=m(v/4)^2/2+Mu^2\to mv^2=mv^2/16+M^2u^2/Mmv2/2=m(v/4)2/2+Mu2→mv2=mv2/16+M2u2/M
2v2=v2/8+(1.5v)2/M→2=1/8+2.25/M→M=1.2kg2v^2=v^2/8+(1.5v)^2/M\to 2=1/8+2.25/M\to M=1.2kg2v2=v2/8+(1.5v)2/M→2=1/8+2.25/M→M=1.2kg Answer.
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