Assume that k=15N/cm=1500N/mk=15N/cm=1500N/mk=15N/cm=1500N/m. So,
k⋅(Δx)22=Afr+mgh;\frac{k\cdot(\Delta x)^2}{2}=A_{fr}+mgh;2k⋅(Δx)2=Afr+mgh;
k⋅(Δx)22=μmgl+mgh;\frac{k\cdot(\Delta x)^2}{2}=\mu mgl+mgh;2k⋅(Δx)2=μmgl+mgh;
h=k⋅(Δx)22mg−μl=1500⋅(0.6)22⋅4⋅9.81−0.2⋅10=4.88mh=\frac{k\cdot(\Delta x)^2}{2mg}-\mu l=\frac{1500\cdot(0.6)^2}{2\cdot 4\cdot 9.81}-0.2\cdot10=4.88mh=2mgk⋅(Δx)2−μl=2⋅4⋅9.811500⋅(0.6)2−0.2⋅10=4.88m
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