The relative velocity of rain is:
"\\overrightarrow{v_{rel}} = \\overrightarrow{v_{rain}} - \\overrightarrow{v_{man}}" Using the Pythagorean theorem, obtain:
"v_{rel} = \\sqrt{v_{rain}^2 + v_{man}^2} = \\sqrt{10^2 + 3^2} = \\sqrt{109} km\/h" Answer. B) "\\sqrt{109} km\/h".
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