Question #126740

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Expert's answer


The relative velocity of rain is:


vrel→=vrain→−vman→\overrightarrow{v_{rel}} = \overrightarrow{v_{rain}} - \overrightarrow{v_{man}}

Using the Pythagorean theorem, obtain:


vrel=vrain2+vman2=102+32=109km/hv_{rel} = \sqrt{v_{rain}^2 + v_{man}^2} = \sqrt{10^2 + 3^2} = \sqrt{109} km/h

Answer. B) 109km/h\sqrt{109} km/h.


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