190 grams of copper was heated from 212 K to 267 k. If the specific heat capacity of Copper is 376.8 J/ (kgK), what was the change in thermal energy of the copper?
The change in thermal energy
Q=cmΔT=376.8⋅0.19⋅(267−212)=3937.56JQ=cm\Delta T=376.8\cdot0.19\cdot(267-212)=3937.56JQ=cmΔT=376.8⋅0.19⋅(267−212)=3937.56J
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