Question #126139

a charged sphere of mass 2.8 kg is suspended from a string. an electric force acts horizontally on the sphere so that the string makes an angle of 33 degree with the vertical when at rest. Find (a) the magnitude of the electric force and (b)the tension in the string.

Expert's answer

The free-body diagram is drawn on the figure below:


Here Fe→\overrightarrow{F_e} is the electric force, T→\overrightarrow{T} is the tension force and mg→\overrightarrow{mg} is the gravity force.

Let's write down the Newton's second law in a projection on the x-axis:

Fe−Tsin⁡θ=0F_e - T\sin\theta = 0

and on the y-axis:


Tcos⁡θ−mg=0T\cos \theta - mg = 0

From the last equation we can find the tension force:


T=mgcos⁡θ=2.8⋅9.81cos⁡33°≈32.75NT = \dfrac{mg}{\cos\theta} = \dfrac{2.8\cdot 9.81}{\cos33\degree} \approx 32.75N

Substituting the expression for TT into the first equation and expressing FeF_e, obtain:


Fe=Tsin⁡θ=mgcos⁡θsin⁡θ=mgtan⁡θF_e =T\sin\theta = \dfrac{mg}{\cos\theta}\sin \theta = mg\tan\theta

Thus:


Fe=2.8⋅9.81⋅tan⁡33°≈17.84NF_e = 2.8\cdot 9.81\cdot \tan33\degree \approx 17.84 N

Answer. (a) the magnitude of the electric force is 17.84 N, (b) the tension in the string is 32.75 N.


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