ω1=2πν1=2π⋅5060=5.23rad/s\omega_1=2\pi\nu_1=2\pi\cdot\frac{50}{60}=5.23rad/sω1=2πν1=2π⋅6050=5.23rad/s
ω2=2πν2=2π⋅105060=109.9rad/s\omega_2=2\pi\nu_2=2\pi\cdot\frac{1050}{60}=109.9rad/sω2=2πν2=2π⋅601050=109.9rad/s
ϵ=ΔωΔt=109.9−5.2320=5.23rad/s2\epsilon=\frac{\Delta\omega}{\Delta t}=\frac{109.9-5.23}{20}=5.23rad/s^2ϵ=ΔtΔω=20109.9−5.23=5.23rad/s2 Answer.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments