The resistance "R" and resistivity "\\rho" of the wire are connected with the following relation:
where "L = 2m" is the lenght of the wire and "A = 0.7mm^2 = 0.7\\cdot 10^{-6}m^2" is the cross sectional area of the wire.
Substituting the numerical values, get:
"R = 4.9\\cdot 10^{-7}\\Omega\\cdot m\\cdot \\dfrac{2m}{0.7\\cdot 10^{-6}m^2} = 1.4\\Omega"
Answer. R = 1.4 Ohms.
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