The kinematic law of motion under the constant acceleration is given be the following equation:
where "d = 41.5m" is the traveled distance, "v_0 = 27 m\/s" is the initial velocity, "a" is the constant acceleration and "t" is the time of motion.
By definition, the acceleration is given by:
where 0 stands for the final velocity (bike stops completely after time "t" passes).
Substituting this expression to the law of motion, get:
Expressing "t" and substituting it to the expression for the acceleration, obtain:
Calculating the numerical value, get:
"a = -\\dfrac{27^2}{2\\cdot 41.5}\\approx -8.78 m\/s^2"
Answer. The acceleration is -8.78 m/s^2.
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