Question #125081

A mass of a gas occupies 20 cm^3 at 5 degree celcius and 760 mm Hg pressure, what is its approximate volume at 30 degree celcius and 800 mm Hg pressure?

Expert's answer

According to the general gas equation, the volume VV, temperature TT and pressure PP of the ideal gas are connected in the following way:


PVT=const\dfrac{PV}{T} = const

Thus, denoting with the index 1 parameters for the initial state and with the index 2 parameters for the final state, obtain:

P1V1T1=P2V2T2\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}

Expressing the final volume from this equation, get:


V2=P1V1T2P2T1V_2 = \dfrac{P_1V_1T_2}{P_2T_1}

Substituting the numerical value (and converting the temperature to kelvin), get:


V2=760⋅20⋅(273+5)800⋅(273+30)≈17.4cm3V_2 = \dfrac{760\cdot 20\cdot (273+5)}{800\cdot (273+30)} \approx 17.4 cm^3

Answer. 17.4 cm^3.


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