Question

A ball is thrown horizontally from the top of a 80 m high cliff. If the initial horizontal velocity is 10.0 m/s, find
(ii) how far from the foot of the cliff it strikes the ground

Answer 1

$$x=vt=v\sqrt{\frac{2h}{g}}\\x=10\sqrt{\frac{2(80)}{9.8}}=40.4\ m$$