Answer to Question #124864 in Physics for Susan Williams

Question

To achieve maximum range for a given initial velocity what will be the angle of projection?

Answer 1

The expression for the range of a body launched with initial velocity $v$ directed $\theta$ degrees above the horizontal is

$$R=\frac{v^2\text{ sin}(2\theta)}{g}.$$

We can see that the range is at maximum when $\theta=45°$.