Answer to Question #124864 in Physics for Susan Williams

Question #124864
To achieve maximum range for a given initial velocity what will be the angle of projection?
1
Expert's answer
2020-07-02T17:15:25-0400

The expression for the range of a body launched with initial velocity vv directed θ\theta degrees above the horizontal is


R=v2 sin(2θ)g.R=\frac{v^2\text{ sin}(2\theta)}{g}.

We can see that the range is at maximum when θ=45°\theta=45°.


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