Answer to Question #124860 in Physics for Mukelo Madolo

Question #124860
The triangular prism with apex angle flux=7o shown above has an index of refraction n=1.66. what is the smallest angle of incidence theta1 for which a light ray can emerge from the other side? Hint: Total internal reflection


NOTE:NEEDED AS FAST AS POSSIBLE,DUE TODAY MIDNIGHT
1
Expert's answer
2020-07-02T17:15:41-0400

Look at the figure:



Start with the minimum angle of incidence 0° relative to the left surface of the prism. Then the incidence angle for the inner surface will be 7°. Calculate whether this is smaller than the critical angle for total internal refraction:

θc=arcsin11.66=37°>7°.\theta_c=\text{arcsin}\frac{1}{1.66}=37°>7°.

Therefore, for the smallest angle of incidence 0° total internal refraction will not occur.

Apply Snell's law to calculate the angle of refraction:


θ=arcsinsin7°1.66=4°.\theta=\text{arcsin}\frac{\text{sin}7°}{1.66}=4°.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment