Answer to Question #124639 in Physics for Dr. Horus

Question

A mass m1=1.8kg is attached to another mass m2=3.2kg with a light inextensible string passing over a frictionless pulley. M2 is surrounded by a viscous liquid. If the acceleration of m2 downward is 0.6m/s^2. Calculate the frictional force acting as a drag on m2.

Answer 1

$$(m_2+m_1)a=(m_2-m_1)g-F_f$$

$$(3.2+1.8)0.6=(3.2-1.8)9.8-F_f$$

$$F_f=10.7\ N$$