Answer to Question #124458 in Physics for kalkidan

Question

water is ejected from a hose of radius 2.5 cm at a speed of 8 m/s. what is the volume of flow rate through the hose?

Answer 1

We can find the volume of flow rate through the hose from the formula:

$Q = Av,$

here, $A = \pi r^2$ is the cross-sectional area of the hose, $v$ is the speed of the water.

Then, we get:

$Q = \pi r^2v,$ $Q = \pi \cdot (0.025 \ m)^2 \cdot 8 \dfrac{m}{s} = 0.016 \ \dfrac{m^3}{s}.$

Answer:

$Q = 0.016 \ \dfrac{m^3}{s}.$