Answer to Question #123726 in Physics for shoaib

Question #123726

if the effective mass of electron is 0.4mo having momentum 2.416*10-16 gram cm/sec then calculate energy of free electron in electron voult at the bottom of conduction brand?

Expert's answer

K=\frac{p^2}{2m}=\frac{(2.416\cdot10^{-16})^2}{2(0.5)(9.109\cdot10^{-31})}=0.064\ J

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