Assume that the formula is Cu2(SO4)3⋅nH2O.
Find the number of moles of Cu2(SO4)3:
n1=M1m1=2⋅64+3(32+16⋅4)319=0.767 mol.
The amount of substance of water was
n2=M2m2=2⋅1+16499−319=10 mol.From the formula Cu2(SO4)3⋅nH2O and the previous calculations, we see the ratio:
n1=n2n1=100.767, n=0.76710=13. Hence, the formula is
Cu2(SO4)3⋅13H2O
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