At different medium the frequency of wave is the same, so
"f=\\frac{v_1}{\\lambda_1}=\\frac{v_2}{\\lambda_2}."Hence, the speed of the water wave in shallow water
"v_2=v_1\\frac{\\lambda_2}{\\lambda_1}=53\\:\\rm cm\/s\\times \\frac{1.6\\;\\rm cm}{4.1\\;\\rm cm}=21\\:\\rm cm\/s"
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