Answer to Question #121066 in Physics for Henshaw

Question

Two parallel plates at a distance of 8.0*10^-5 apart are maintained at a p.d of 600 volts with the negative plate earthed.what is the electric field strength?

Answer 1

We can find the electric field strength from the formula:

$$E = \dfrac{V}{d} = \dfrac{600 \ V}{8.0 \cdot 10^{-5} \ m} = 7.5 \cdot 10^6 \ \dfrac{V}{m}.$$

Answer:

$E = 7.5 \cdot 10^6 \ \dfrac{V}{m}.$