Answer to Question #120307 in Physics for daniel

Question #120307
Q3. What is the wavelength of the x-ray emitted from a Tungsten target (Z=74) when an electron moves from the M-shell (n=3) to the K-shell (n=1)
1
Expert's answer
2020-06-08T10:16:38-0400

The change in electron's energy is


ΔE=(13.6 eV)Z2(1nM21nK2).\Delta E=(-13.6\text{ eV})Z^2\bigg(\frac{1}{n_M^2}-\frac{1}{n_K^2}\bigg).

The wavelength is


λ=hcΔE=hc(13.6 eV)(1.6021019 J/eV)Z2(1nM21nK2)= =444 μm.\lambda=\frac{hc}{\Delta E}=\frac{hc}{(-13.6\text{ eV})(1.602\cdot10^{-19}\text{ J/eV})Z^2\bigg(\frac{1}{n_M^2}-\frac{1}{n_K^2}\bigg)}=\\\space\\ =444\text{ μm}.

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