The energy of each photon with wavelength "\\lambda":
"E_1=h\\nu=h\\frac{c}{\\lambda}."
The electrical energy required to provide 12 W during 16 ms:
"E=Pt." This energy will be enough for N photons:
"Pt=N\\cdot h\\frac{c}{\\lambda},\\\\\n\\space\\\\\nN=\\frac{Pt\\lambda}{hc}=\\frac{12(16\\cdot10^{-3})(400\\cdot10^{-9})}{(6.626\\cdot10^{-34})(3\\cdot10^8)}=3.87\\cdot10^{17}."
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