Answer to Question #119739 in Physics for Lindon

Question #119739
A certain test charge is placed in an electric field. The test charge has a magnitude of 5 µC and it experiences a force of 25 µN. What is the strength of the electric field in the location of the test charge?
1
Expert's answer
2020-06-03T12:03:14-0400

By definition, the force FF experienced by the charge qq is given by the following expression:


F=qEF = qE

where EE is the strength of the electric field in the location of the charge.

Expressing EE from this equation, get:


E=F/q=25μN/5μC=5V/mE = F/q = 25 \mu N/5\mu C = 5V/m

Answer. E = 5 V/m.


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