Question

A certain test charge is placed in an electric field. The test charge has a magnitude of 5 µC and it experiences a force of 25 µN. What is the strength of the electric field in the location of the test charge?

Answer 1

By definition, the force $F$ experienced by the charge $q$ is given by the following expression:

$$F = qE$$

where $E$ is the strength of the electric field in the location of the charge.

Expressing $E$ from this equation, get:

$$E = F/q = 25 \mu N/5\mu C = 5V/m$$

Answer. E = 5 V/m.