Question

A bottle rocket is launched from the ground with a velocity of 30.0 m/s upward.
a) What is the maximum height of the bottle rocket? ________________________
b) How long will it take the bottle rocket to reach its max height? ________________________
c) How long will it take the bottle rocket to land? ________________________
d) What will be the bottle rocket’s velocity at landing?

Answer 1

Given:

${v_0=30.0\:\rm m/s;} \\ g=9.81\;\rm m/s^2.$

a)

$$h_{\rm max}=\frac{v_0^2}{2g}=\frac{30.0^2}{2\times 9.81}=45.9\:\rm m$$

b)

$$t_1=\frac{v_0}{g}=\frac{30.0}{9.81}=3.06\:\rm s$$

c)

$$t_2=2t_1=2\times 3.06=6.12\:\rm s$$

d)

$$v_f=v_0=30.0\:\rm m/s \quad (downward)$$