The line shape will be
"G=\\frac{1}{\u03c3\\sqrt{2\u03c0}}\\text{exp}\\bigg(\u2212\\frac{(\u03bd-\u03bd_0)^2}{2\u03c3^2}\\bigg),\\\\\\space\\\\\n\u03c3 = \\frac{\u03bd_0}{c}\\sqrt{\\frac{2kT\\text{ ln}2}{m}}."With
ν0=104 Hz,
T=300 K,
c=300 000 000 m/s,
m=7.308x10-26 kg, or 44.01 amu,
we get
"\\sigma=9.34\\cdot10^{-3},\\\\\n\\space\\\\G(\\nu)=42.7\\text{ exp}\\bigg(-\\frac{(\\nu-10^4)^2}{1.74\\cdot10^{-4}}\\bigg):"
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