Question

The pressure of 3 moles of an ideal gas at a temperature of 27 having a volume of
10-3m3

Answer 1

The equation of the ideal gas is:

$$pV = \mu RT$$

where $p$ is the pressure, $V$ is the volume, $\mu$ is the number of moles, $T$ is the absolte temperature and $R = 8.31 \dfrac{J}{mol\cdot K}$ is the ideal gas constant.

Expressing the pressure from this equation get:

$$p = \frac{\mu RT}{V} = \frac{3\cdot 8.31\cdot (27 + 273)}{10^{-3}} = 7.479\cdot 10^{6} Pa = 7.479 MPa$$

Answer. p = 7.479 MPa.