Question

A pipe, open at both ends, is sounding its fundamental note. calculate the frequency of the note if the pipe is 56 cm long. Neglect end corrections of the pipe. Take the speed of sound in air as 350 m/s.

Answer 1

The fundamental note (frequency) in terms of length of the pipe and the speed of sound is

$$f_0=\frac{v}{2L}=\frac{350}{2\cdot0.56}=312.5\text{ Hz}.$$