Question

A man cleaning a floor pulls a vacuum cleaner with a force of magnitude F = 34.6 N at an angle of 12.5˚ with the horizontal. Calculate the work done by the force on the vacuum cleaner as the vacuum cleaner is displaced 4.87 m to the right.

Answer 1

The work done by the force can be calculated according to the following equation:

$$W=Fd\text{ cos}\theta=34.6\cdot4.87\cdot\text{cos}12.5°=165\text{ J}.$$