Answer to Question #117370 in Physics for bloom

Question

Starting from rest a 0.064-kg arrow is fired horizontally. The bowstring exerts a horizontal average force of 81 N on the arrow over a distance of 0.77 m. With what horizontal speed does the arrow leave the bow?

Answer 1

From the conservation of energy:

$$0.5mv^2=Fs$$

$$0.5(0.064)v^2=(81)(0.77)$$

$$v=44\frac{m}{s}$$