The law of motion of the object falling from height "H"is "y(t) = H - \\frac{g t^2}{2}", where "g" is the acceleration of the gravity. When the object hits the surface "y(t) = 0", from where "t = \\sqrt{\\frac{2 H}{g}}".
Substituting "H = 1.4 m" and "g = 1.67 \\frac{m}{s^2}" into the last formula, obtain "t \\approx 1.3 s".
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