Question

If 3.0x105 J of work was done moving a box 10.0 m, calculate the force applied to the box over that distance.

Answer 1

The work needed to move an object by the constant force $F$ by displacement $s$ is $A = F \cdot s$, from where $F = \frac{A}{s} = \frac{3.0 \cdot 10^5 J}{10 m} = 3 \cdot 10^4 N = 30kN$.