Question

An automobile on an expressway is accelerating at 25 ft/s2. If it started from rest and has been accelerating for
5.56 s., how far has it travelled during this time of acceleration?

Answer 1

The distance traveled by a car

$$d=v_0t+\frac{at^2}{2}\\ =0\times 5.56+\frac{25\times 5.56^2}{2}=386 \:\rm ft$$