Question #114374
A particle of mass 3kg, on a smooth surface, is acted upon by a force F. If the
acceleration produced in the particle is 2ms-1

, find the magnitude of F.
1
Expert's answer
2020-05-07T10:19:43-0400

The Newton's second law says

F=ma=(3kg)×(2m/s2)=6N.F=ma=(3\:\rm kg)\times (2\:\rm m/s^2)=6\:\rm N.

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