Answer to Question #113779 in Physics for Harish

Question #113779
In a youngs double slit experiment the ratio of light mxima to minina close to the central fringe on the screen is 9:1. The ratio of slit width is
1
Expert's answer
2020-05-04T12:40:16-0400
91=ImaxImin=(I2+I1)2(I2I1)2\frac{9}{1}=\frac{I_{max}}{I_{min}}=\frac{(\sqrt{I_{2}}+\sqrt{I_{1}})^2}{(\sqrt{I_{2}}-\sqrt{I_{1}})^2}

31=I2I1+1I2I11\frac{3}{1}=\frac{\sqrt{\frac{I_2}{I_1}}+1}{\sqrt{\frac{I_2}{I_1}}-1}

I2I1=2\sqrt{\frac{I_2}{I_1}}=2

I2I1=4\frac{I_2}{I_1}=4


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