Question #113630

Newton`s second law of motion with free body diagram (FBD)


1. A 300g eraser rests on a table what is its normal force?


2. The eraser in #1 is placed in a table inclined @ 40°. What is its new normal force? Assume that the eraser is not sliding.


3. If the eraser in #2 begins sliding, what force parallel to the eraser is needed to prevent it from moving?

Expert's answer

1.



N=mg=0.3(9.8)=2.94 NN=mg=0.3(9.8)=2.94\ N

2.


N=mgcos⁡40=0.3(9.8)cos⁡40=2.25 NN=mg\cos{40}=0.3(9.8)\cos{40}=2.25\ N

3.


F=mgsin⁡40=0.3(9.8)sin⁡40=1.89 NF=mg\sin{40}=0.3(9.8)\sin{40}=1.89\ N


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