2020-05-01T02:37:13-04:00
what is the image distance and image height if a 7 cm tall object is placed is 50 cm from a concave mirror having a focal lenght of 10 cm long?
1
2020-05-04T12:47:49-0400
1 f = 1 d 0 + 1 d i → 1 10 = 1 50 + 1 d i \frac{1}{f}=\frac{1}{d_0}+\frac{1}{d_i}\to \frac{1}{10}=\frac{1}{50}+\frac{1}{d_i} f 1 = d 0 1 + d i 1 → 10 1 = 50 1 + d i 1
d i = 12.5 c m d_i=12.5\ cm d i = 12.5 c m
m = − 12.5 50 = − 0.25 m=-\frac{12.5}{50}=-0.25 m = − 50 12.5 = − 0.25
h i = m h o = − 0.25 ( 7 ) = − 1.75 c m h_i=mh_o=-0.25(7)=-1.75\ cm h i = m h o = − 0.25 ( 7 ) = − 1.75 c m
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