Question

A cannon ball is projected so as to attain a maximum range. Find the maximum height attained if the initial velocity is u

Answer 1

A cannon ball is projected so as to attain a maximum range. Thus, the angle is

$$\alpha=45\degree$$

So

$$H=\frac{u^2\sin^2{45}}{2g}=\frac{u^2(0.5)}{2g}$$

$$H=\frac{u^2}{4g}$$