The equations of motion of the package are y(t)=h−2gt2, x(t)=v0t, where h is the initial altitude, v0 - initial velocity of the package.
Equating altitude to zero, one can find the time T it will take to reach the ground: 0=h−2gT2⇒T=g2h.
Therefore, the horizontal distance before dropping the package should be L=x(T)=v0T=v0g2h≈2197.8m.
Comments
Leave a comment