Question #111935
A stove has a surface temperature of 500 K. The room it is in has a temperature of 310 K. The emissivity of the stove is 0.9, and its surface area is 4.5 m2. What is the net power radiated into the room by the stove?
1
Expert's answer
2020-04-28T09:47:21-0400
P=eσA(T24T14)P=e\sigma A(T_2^4-T_1^4)

P=(0.9)(5.67108)(4.5)(50043104)=12231 WP=(0.9)( 5.67 \cdot 10^{−8} )(4.5)(500^4-310^4)\\=12231\ W


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