Question #111933
An undersea thermal vent emits ocean water which was superheated by a magma chamber below the ocean floor. The temperature of the superheated water is 400° C. A submersible sends a steel probe of volume 0.0008 m3 through the heated water from the surrounding cold ocean t 5° C. By how much does the volume of the steel probe change? Take steel = 36 x 10-6 (°C)-1.
1
Expert's answer
2020-04-28T09:48:08-0400
ΔV=βVΔT\Delta V=\beta V\Delta T

ΔV=(36106)(0.0008)(4005)=1.1105 m3\Delta V=(36\cdot 10^{-6} )(0.0008)(400-5)=1.1\cdot 10^{-5}\ m^3


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