The power of the heater is "P = I U = 12 A \\cdot 120 V = 1440W = 1.44kW".
The duration of a 30 day month is "t = 30 \\cdot 24 h = 720 h", hence the amount of energy the heater will consume if stayed on all the time is "1.44 kW \\cdot 720 h = 1036.8 kW \\cdot h".
This will cost "0.12 \\$ \\cdot 1036.8 kW \\cdot h \\approx 124.42 \\$."
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