Question

A cubic sample of a new kind of artificial tissue is subject to an increase in pressure of 160 kPa which results in a reduction in the side length of the cube of 6.5%. That is, the side length of the cube has reduced from L0 to 0.935L0.

What is the bulk modulus of this tissue? (to 2 s.f and in MPa)

Answer 1

$$K=-\frac{\Delta P}{\frac{\Delta V}{V}}=\frac{\Delta P}{1-\frac{L^3}{L^3_0}}$$

$$K=\frac{0.16}{1-0.935^3}=0.88\ MPa$$