Answer to Question #110892 in Physics for Kew Ming Hui

Question

An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal

Answer 1

$h=\frac{(v\sin{25})^2}{2g}=\frac{(20\sin{25})^2}{2(9.8)}=3.64\ m$

$t=\frac{2(v\sin{25})}{g}=\frac{2(20\sin{25})}{(9.8)}=1.72\ s$

$R=v\cos{25}t=20\cos{25}(1.72)=31.26\ m$