Solution.
"\\upsilon_1 = 150 km\/hr = 41.7 m\/s;"
"\\upsilon_2 = 250 km\/hr = 69.4 m\/s;"
"\\upsilon = \\sqrt{\\upsilon_2^2 - \\upsilon_1^2};"
"\\upsilon = \\sqrt{69.4^2 - 41.7^2}= 55.57 m\/s" - the length of the north vector;
Answer: "\\upsilon = 55.57 m\/s."
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