Question #109604
a 5.6k block is sliding across a surface while experiencing a force of 55N. the block has a displacement of 7.5 meters. what is the work done on the box ?
1
Expert's answer
2020-04-15T10:18:50-0400

The work done on the box

W=Fd=(55 N)×(7.5 m)=412.5 J.W=Fd=(55\:\rm N)\times (7.5\:\rm m)=412.5\:\rm J.

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