Answer to Question #109143 in Physics for Shubham Kumar

Question

Q.) A bomb of mass 300kg fragmented into two parts :one having mass 200kg moving with a velocity of 16m/s² and other having mass 100kg.Find out total kinetic energy produced in this bombarding

Answer 1

The speed of second part of a bomb we can fin using the law of conservation of momentum

$0=m_1v_1-m_2v_2.$

Hence,

$v_2=m_1v_1/m_2=200\times 16/100=32\:\rm m/s.$

The total kinetic energy

$K=\frac{m_1v_1^2}{2}+\frac{m_2v_2^2}{2}=\\ =\frac{200\times 16^2}{2}+\frac{100\times 32^2}{2}=76800\:\rm J.$