Answer to Question #108996 in Physics for Boluwatife

Question

a body a body of mass 2 kg is placed on a rough inclined plane whose angle of inclination of 30-degree. find the resultant force acting down the slope to the acceleration. If a frictional force of 5 Newton acts between the body and the inclined surface.

Answer 1

The resultant force acting down the slope is projection of force of gravity minus frictional force: $F = m g \sin \theta - F_f$.

Given that $\theta = 30^{\circ}$, $m = 2 kg$ and $F_f = 5 N$, the resultant force is $F = 2 kg \cdot 9.81 \frac{m}{s^2} \cdot 0.5 - 5 N = 4.81 N$.