Question #108655
A train starts from rest and travels 10 seconds with acceleration a=4-0.3t, then runs for 30 seconds at constant velocity and finally comes to rest by decelerating at 3 m/s^2. Determine the MAGNITUDE of the CONSTANT VELOCITY in m/s.
1
Expert's answer
2020-04-09T09:16:03-0400

v0=0v_0=0 - A train starts from rest

t=10st=10s - the time with acceleration

a=40.3ta=4-0.3t


aavr=a(t0=0)+a(t10=10)t10t0=0+110=0.1a_{avr}=\frac{a(t_0=0)+a(t_{10}=10)}{t_{10}-t_0}=\frac{0+1}{10}=0.1


v=v0+aavrt22v=0+0.11022=5v=v_0+\frac{a_{avr}t^2}{2}\\ v=0+\frac{0.1 \cdot 10^2}{2}=5 m/s


Answer: 5 m/s



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