Question

Ben throws a rock at an angle 45° from horizontal on level ground. He throws the rock with a velocity of 30m/s. Create a acc vs. t graph, a v vs. t graph and a displacement vs. time graph for the x and y directions.

Answer 1

As the rock is thrown at an angle 45 then there will be two component of velocity

one being the $v_x=30\cos45^o$ and $v_y=30\sin45^o$

as acceleration is only in y direction then $a_x=0$ and $a_y=-10m/s^2$

hence graph of acceleration will be a straight line for for y and zero for x direction

let's see for velocity

v=u+at

for x : $v_x=u_x=15\sqrt2(a_x=0)$

for y :$v_y=u_y+a_yt=15\sqrt2-10t$

let's see for displacement

s=ut+0.5at²

for x: $S=15\sqrt2t+0 =15\sqrt2t$

for y: $S=15\sqrt2t-5t^2$