As per the given question,
Internal diameter of the pipe (d)=15cm(d) =15cm(d)=15cm
Opening of the pipe is 17m below, let the velocity of the water at the below is v
Now, applying the bernaulli theorem,
ρgh+ρv22=constant\rho gh+\dfrac{\rho v^2}{2}=constantρgh+2ρv2=constant
v=2ghv=\sqrt{2gh}v=2gh
v=2×9.8×17=18.25m/secv=\sqrt{2\times 9.8\times 17}=18.25m/secv=2×9.8×17=18.25m/sec