As per the given question,
Internal diameter of the pipe "(d) =15cm"
Opening of the pipe is 17m below, let the velocity of the water at the below is v
Now, applying the bernaulli theorem,
"\\rho gh+\\dfrac{\\rho v^2}{2}=constant"
"v=\\sqrt{2gh}"
"v=\\sqrt{2\\times 9.8\\times 17}=18.25m\/sec"
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