Question #108473

A large reservoir is drained through a pipe with an internal diameter of 15 cm.

If the opening of the pipe is 17 m below the surface of the water in the reservoir then at what speed is the water exiting the pipe?

(treat water as an incompressible non-viscous fluid)

Expert's answer

As per the given question,

Internal diameter of the pipe (d)=15cm(d) =15cm

Opening of the pipe is 17m below, let the velocity of the water at the below is v

Now, applying the bernaulli theorem,

ρgh+ρv22=constant\rho gh+\dfrac{\rho v^2}{2}=constant

v=2ghv=\sqrt{2gh}

v=2×9.8×17=18.25m/secv=\sqrt{2\times 9.8\times 17}=18.25m/sec


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