Question

a positive charge of 3.6x10^-5 C and a negative charge of 2.4x10^-5 C are 0.034 meters apart calculate the magnitude of the electrostatic force between the two particles

Answer 1

$$F=\frac{kq_1q_2}{r^2}$$

$$F=\frac{(9\cdot 10^9)(3.6\cdot 10^{-5})(2.4\cdot 10^{-5})}{0.034^2}=6700\ N=6.7\ kN$$